x+2log(2x^2+x)=1

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Solution for x+2log(2x^2+x)=1 equation:


Simplifying
x + 2log(2x2 + x) = 1

Reorder the terms:
x + 2glo(x + 2x2) = 1
x + (x * 2glo + 2x2 * 2glo) = 1
x + (2glox + 4glox2) = 1

Reorder the terms:
2glox + 4glox2 + x = 1

Solving
2glox + 4glox2 + x = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1x' to each side of the equation.
2glox + 4glox2 + x + -1x = 1 + -1x

Combine like terms: x + -1x = 0
2glox + 4glox2 + 0 = 1 + -1x
2glox + 4glox2 = 1 + -1x

Reorder the terms:
-1 + 2glox + 4glox2 + x = 1 + -1x + -1 + x

Reorder the terms:
-1 + 2glox + 4glox2 + x = 1 + -1 + -1x + x

Combine like terms: 1 + -1 = 0
-1 + 2glox + 4glox2 + x = 0 + -1x + x
-1 + 2glox + 4glox2 + x = -1x + x

Combine like terms: -1x + x = 0
-1 + 2glox + 4glox2 + x = 0

The solution to this equation could not be determined.

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